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Derive the relation between the wavelen...

Derive the relation between the wavelength `(lambda)` of the de broglie wave and kinetic energy `(E )` of a moving particle

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The correct Answer is:
According to de-Broglie, the wavelength associated with a particle of mass `m`, moving with velocity `v` is given by the relation, `lambda=(h)/(mv)`
where `h` is Planck's constant
`1/2mv^(2)=KE`
`m^(2)v^(2)=2m KE`
`mv=sqrt(2mKE)`
`lambda=(h)/sqrt(2mKE)`
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