The Vividh Bharati Station of All india Radio, Delhi broadcasts on a frequency of `1368 kHz` (kilo hertz). Calculate the wavelength and which part of the electromagnetic spectrum does it belong to

Explanation

To solve the problem of calculating the wavelength of the radio broadcast from the Vividh Bharati Station of All India Radio, Delhi, and determining which part of the electromagnetic spectrum it belongs to, we can follow these steps:

### Step 1: Understand the relationship between frequency and wavelength
The relationship between the speed of light (C), frequency (μ), and wavelength (λ) is given by the formula:
\[ \lambda = \frac{C}{\mu} \]
where:
- \( \lambda \) is the wavelength,
- \( C \) is the speed of light (approximately \( 3 \times 10^8 \) meters per second),
- \( \mu \) is the frequency in hertz.

### Step 2: Convert the frequency from kilohertz to hertz
The frequency is given as \( 1368 \, \text{kHz} \). To convert this to hertz:
\[ \mu = 1368 \, \text{kHz} = 1368 \times 10^3 \, \text{Hz} = 1.368 \times 10^6 \, \text{Hz} \]

### Step 3: Substitute the values into the wavelength formula
Now, we can substitute the values of \( C \) and \( \mu \) into the wavelength formula:
\[ \lambda = \frac{3 \times 10^8 \, \text{m/s}}{1.368 \times 10^6 \, \text{Hz}} \]

### Step 4: Calculate the wavelength
Perform the division to find \( \lambda \):
\[ \lambda = \frac{3 \times 10^8}{1.368 \times 10^6} \approx 219.3 \, \text{meters} \]

### Step 5: Determine the part of the electromagnetic spectrum
The frequency of \( 1368 \, \text{kHz} \) falls within the range of radio waves. The radio wave part of the electromagnetic spectrum typically includes frequencies below \( 10^6 \, \text{Hz} \) (or \( 1 \, \text{MHz} \)). Since \( 1368 \, \text{kHz} \) is below \( 1 \, \text{MHz} \), it confirms that this frequency belongs to the radio wave spectrum.

### Final Answer
The wavelength of the broadcast is approximately \( 219.3 \, \text{meters} \), and it belongs to the radio wave part of the electromagnetic spectrum.

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