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An electron practically at rest, is init...

An electron practically at rest, is initially accelerated through a potential difference of 100 volts. It then has a de Broglie wavlength `=lambda_(1)Å`. It then get retorted through 19 volts and then has a wavelength `lambda_(2)Å` . A further retardation through 32 volts changes the wavelength to `lambda_(3)`. What is the value of `(lambda_(3)-lambda_(2))/(lambda_(1))`?

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The correct Answer is:
`20/63`
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RESONANCE ENGLISH-NUCLEAR CHEMISTRY-Exercise-1
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