Write equations for the following transformation:
(a) `._(7)^(17)N (n, p)` (b) `._(19)^(39)K(n, alpha)`

Explanation

To solve the problem, we need to write the equations for the given nuclear transformations. Let's break it down step by step for each part.

### Part (a): Transformation of Nitrogen-17

1. **Identify the Reactants and Products**:
- We have Nitrogen-17, which is represented as \( _{7}^{17}N \).
- It reacts with a neutron, represented as \( _{0}^{1}n \).
- The products of the reaction are Carbon-14, represented as \( _{6}^{14}C \), and a proton, represented as \( _{1}^{1}H \).

2. **Write the Nuclear Reaction Equation**:
- The equation can be written as:
\[ _{7}^{17}N + _{0}^{1}n \rightarrow _{6}^{14}C + _{1}^{1}H \]

### Part (b): Transformation of Potassium-39

1. **Identify the Reactants and Products**:
- We have Potassium-39, represented as \( _{19}^{39}K \).
- It reacts with a neutron, represented as \( _{0}^{1}n \).
- The products of the reaction are Chlorine-36, represented as \( _{17}^{36}Cl \), and an alpha particle, represented as \( _{2}^{4}He \).

2. **Write the Nuclear Reaction Equation**:
- The equation can be written as:
\[ _{19}^{39}K + _{0}^{1}n \rightarrow _{17}^{36}Cl + _{2}^{4}He \]

### Final Equations

- For part (a):
\[ _{7}^{17}N + _{0}^{1}n \rightarrow _{6}^{14}C + _{1}^{1}H \]

- For part (b):
\[ _{19}^{39}K + _{0}^{1}n \rightarrow _{17}^{36}Cl + _{2}^{4}He \]