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The ratio of slopes of K(max) vs. V and ...

The ratio of slopes of `K_(max)` vs. V and `V_(0)` vs. v curves in the photoelectric effect gives (v= freqency. `K_(max)`= maximum kinetic energy, `V_(0)`=stopping potential) :

A

charge of electron

B

Planck's constant

C

work function

D

the ratio of Planck's constant of electronic charge

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A
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Slope of V_(0) vs v curve is (where V_(0) = Stopping potential, v=subjected freqency)

This question has statement - 1 and statement - 2 of the four choice given after the statements choose the one that best describes the two statements statement - 1 : A metallic surface is irradiated by a monochromatic light of frequency v gt v_(0) (the threshold frequency). The maximum kinetic energy and the stopping potential are K_(max) and V_(0) respectively if the frequency incident on the surface is doubled , both the K_(max) and V_(0) are also doubled statement - 2 : The maximum kinetic energy and the stopping potential of photoelectron emitted from a surface are linearly dependent on the frequency of incident light

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The stopping potential in an experiment on photoelectric effect is 2V. What is the maximum kinetic energy of the photoelectrons emitted ?

The stopping potential in an experiment on a photo electric effect is 1.5 V. What is the maximum kinetic energy of the photoelectrons emitted?

The emission of electrons from a metal surface exposed rto light radaition of appropriate wavelength is called photoelectroic effect .The emmited electron are called photo=-weklectron work function of threshold energy may be defined as the minimum amount of energy required to ejercted electron from a most surface .According to Einstein Maximum kinetic energy of ejected electron = Aborbed energy - Work function (1)/(2) mv_(max)^(2) = h(v) - h(v_(n)) = hv [(1)/(lambda) -0 (1)/(lambda_(n))] Where v_(n) and lambda_(0) are thereshold frequency and threshold wavelength respectively Sopping potential : it is the miximum potential at which the photoelectric current becomes zero if V_(0) is the stopping potential eV_(0) = h(v- v_(0)) Whaich of the following is the graph between the frequency (V) of the incident radiation and the stopping potential (v) ?

The emission of electrons from a metal surface exposed rto light radaition of appropriate wavelength is called photoelectroic effect .The emmited electron are called photo=-weklectron work function of threshold energy may be defined as the minimum amount of energy required to ejercted electron from a most surface .According to Einstein Maximum kinetic energy of ejected electron = Aborbed energy - Work function (1)/(2) mv_(max)^(2) = h(v) - h(v_(n)) = hv [(1)/(lambda) -0 (1)/(lambda_(n))] Where v_(n) and lambda_(0) are thereshold frequency and threshold wavelength respectively Sopping potential : it is the miximum potential at which the photoelectric current becomes zero if V_(0) is the stopping potential eV_(0) = h(v- v_(0)) The stopping potential as a function on electron frtequency is plotted for two photoelectric surface A abd B The graph show that the work function of A is

When a metallic surface is illuminated by a monochromatic light of lamda the stopping potential for photoelectric current is 4V_(0) when the same surface is illuminated by light of wavelength 3 lamda the stopping potential is V_(0) The threshold wavelength for this surface for photoelectric effect is -

If the threshold frequency of a metal for photoelectric effect is v_(0) then which of the following will not happen ?

Explain giving reasons for the following : (a) Photoelectric current in a photocell increases with the increase in intensity of the incident radiation. (b) The stopping potential V_0 varies linearly with the frequency nu of the incident radiation for a given photosensitive surface with the slope remaining the same for different surfaces. (c) Maximum kinetic energy of the photoelectrons is independent of the intensity of incident radiation.

RESONANCE ENGLISH-NUCLEAR CHEMISTRY-Exercise-2
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