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Electron in a sample of H- atoms make tr...

Electron in a sample of `H-` atoms make transitions from state `n=x` to some lower excited state. The emission spectrum from the sample is found to contain only the lines belonging to a particular series. If one of the photons had an energy of `0.6375 eV`. Then find the value of `x. [" Take " 0.6375eV=(3)/(4)xx0.85eV]`.

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The correct Answer is:
8
Energy of the photon`=0.6375 eV=3/4xx0.85 eV=3/4xx13.6/4^(2)=13.6/4^(2)(1-1/4)=13.6(1/4^(2)-1/8^(2))`
Thus, this photon coresponds to transition `n=8` to `n=4` (Brakett series)
`:. X=8` Ans.
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