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Which of the following statement is//are...

Which of the following statement is//are correct for an electron of quantum numbers `n=4` and `m=2`?

A

The value of `l` may be `2`

B

The value of `l` may be `3`

C

The value of `s` may be `+1//2`

D

The value of `l` may be `0, 1, 2, 3.`

Text Solution

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The correct Answer is:
To determine which statements are correct for an electron with quantum numbers \( n = 4 \) and \( m = 2 \), we need to analyze the quantum numbers and their implications. ### Step-by-Step Solution: 1. **Understanding Quantum Numbers**: - The principal quantum number \( n \) indicates the energy level of the electron. In this case, \( n = 4 \) means the electron is in the fourth energy level. - The azimuthal quantum number \( l \) (often represented as \( L \)) determines the shape of the orbital and can take values from \( 0 \) to \( n-1 \). Therefore, for \( n = 4 \), \( l \) can be \( 0, 1, 2, \) or \( 3 \). - The magnetic quantum number \( m \) (or \( m_l \)) can take values from \( -l \) to \( +l \). Given \( m = 2 \), this means \( l \) must be at least \( 2 \) (since \( m \) cannot exceed \( l \)). 2. **Determining Possible Values of \( l \)**: - Since \( n = 4 \), the possible values of \( l \) are \( 0, 1, 2, 3 \). - However, since \( m = 2 \), the only valid values for \( l \) are \( 2 \) and \( 3 \) (as \( m \) must be less than or equal to \( l \)). 3. **Determining Possible Values of Spin \( s \)**: - The spin quantum number \( s \) can only be \( +\frac{1}{2} \) or \( -\frac{1}{2} \). Therefore, the electron can have either of these two values. 4. **Evaluating the Statements**: - **Statement A**: "Value of \( l \) may be \( 2 \)" - This is correct since \( l \) can indeed be \( 2 \). - **Statement B**: "Value of \( l \) may be \( 3 \)" - This is also correct since \( l \) can be \( 3 \). - **Statement C**: "Value of \( s \) may be \( +\frac{1}{2} \)" - This is correct as \( s \) can be either \( +\frac{1}{2} \) or \( -\frac{1}{2} \). - **Statement D**: "Value of \( l \) may be \( 0, 1, 2, 3 \)" - This is incorrect because \( l \) cannot be \( 0 \) or \( 1 \) in this case. 5. **Conclusion**: - The correct statements are A, B, and C. Statement D is incorrect. ### Final Answer: The correct statements for an electron with quantum numbers \( n = 4 \) and \( m = 2 \) are: - A: Value of \( l \) may be \( 2 \) (Correct) - B: Value of \( l \) may be \( 3 \) (Correct) - C: Value of \( s \) may be \( +\frac{1}{2} \) (Correct) - D: Value of \( l \) may be \( 0, 1, 2, 3 \) (Incorrect)

To determine which statements are correct for an electron with quantum numbers \( n = 4 \) and \( m = 2 \), we need to analyze the quantum numbers and their implications. ### Step-by-Step Solution: 1. **Understanding Quantum Numbers**: - The principal quantum number \( n \) indicates the energy level of the electron. In this case, \( n = 4 \) means the electron is in the fourth energy level. - The azimuthal quantum number \( l \) (often represented as \( L \)) determines the shape of the orbital and can take values from \( 0 \) to \( n-1 \). Therefore, for \( n = 4 \), \( l \) can be \( 0, 1, 2, \) or \( 3 \). - The magnetic quantum number \( m \) (or \( m_l \)) can take values from \( -l \) to \( +l \). Given \( m = 2 \), this means \( l \) must be at least \( 2 \) (since \( m \) cannot exceed \( l \)). ...
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Knowledge Check

  • Which of the following sets of quantum numbers is correct for an electron in 4f orbital?

    A
    `n=4, l=3, m=+4, s=+1/2`
    B
    `n=4, l=4, m=-4, s=-1/2`
    C
    `n=4, l=3, m=+1, s=+1/2`
    D
    `n=3, l=2, m=-2, s=+1/2`
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