Home
Class 12
CHEMISTRY
The kinetic energy of an electron in the...

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [`a_(0)` is Bohr radius] :

A

`h^(2)/(4pi^(2)ma_(0)^(2))`

B

`h^(2)/(16 pi^(2)ma_(0)^(2))`

C

`h^(2)/(32pi^(2)ma_(0)^(2))`

D

`h^(2)/(64pi^(2) ma_(0)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`mv (4a_(0))=h/pi` so, `v=h/(4mpia_(0))` so `KE=1/2 mv^(2)=1/2 m. (h^(2))/(16m^(2)pi^(2)a_(0)^(2))=(h^(2))/(32mpi^(2) a_(0)^(2))`
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    RESONANCE ENGLISH|Exercise PART-II|26 Videos

  • NUCLEAR CHEMISTRY

    RESONANCE ENGLISH|Exercise ADVANCED LEVEL PROBLEMS|30 Videos

  • NUCLEAR CHEMISTRY

    RESONANCE ENGLISH|Exercise PART-IV : COMPREHENSION|13 Videos

  • NITROGEN CONTAINING COMPOUNDS

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Nitrogen containing Compounds)|30 Videos

  • P BLOCK ELEMENTS

    RESONANCE ENGLISH|Exercise PART -II|23 Videos

Similar Questions

Explore conceptually related problems

The kinetic energy of the electron in the second Bohr's orbit of a hydrogen atom [ a_(0) is Bohr's radius] is

The energy of an electron present in Bohr's second orbit of hydrogen atom is

Radius of Bohr's orbit of hydrogen atom is

Radius of Bohr's orbit of hydrogen atom is

The radius of second Bohr’s orbit of Hydrogen atom is:

Determine wavelength of electron in 4th Bohr's orbit of hydrogen atom

Calculate the velocity of an electron in the first Bohr orbit of a hydrogen atom

The energy of an electron in the first Bohr's orbit of a hydrogen atom is -2.18 xx10^(-18)J . Its energy in the second orbit would be

Radius of tenth Bohr orbit of the Hydrogen atoms is

Calculate angular momentum of an electron in the third Bohr orbit of hydrogen atom.