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Energy of an electron is given by E=-2...

Energy of an electron is given by
`E=-2.178'10^(-18)J`
Wavelength of light required to excite an electron in an hydrogen atom from level n = 1 to n = 2 will be `(h = 6.62 xx 10^(−34) Js and c = 3.0 xx 10^(8) ms^(−1))`

A

`1.214xx10^(-7) m`

B

`2.816xx10^(-7) m`

C

`6.500xx10^(-7) m`

D

`8.500xx10^(-7) m`

Text Solution

Verified by Experts

The correct Answer is:
1
`DeltaE=2.178xx10^(-18)(1/1^(2)-1/2^(2))=(hC)/lambda`
`2.178xx10^(-18)(1/1^(2)-1/2^(2))=(6.62xx10^(-34)xx3.0xx10^(8))/(lambda)" " :. lambda~~1.214xx10^(-7)m`
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