Calculate the minimum and maximum number of electrons which may have magnetic quantum number `m=+1` and spin quantum number `s=+(1)/(2)` in chromium (Cr)
(a)0,1
(b)1,2
(c)4,6
(d)2,3

Options

A. `0, 1`
B. `1, 2`
C. `4, 6`
D. `2, 3`

Answer

4

Explanation

Out of `6` electrons in `2p` and `3p` must have on electron with `m=+1` and `s=1/2` but in `3d`-subshell an orbital having `m=+1` may have quantum no. `-1/2` or `+1/2`. Therefore, minimum and maximum posible values are `2` and `3` respectively.