Oxidation Number of N in `N_2H_5^+`

Answer

To find the oxidation number of nitrogen (N) in the ion \( N_2H_5^+ \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the oxidation number of hydrogen (H)**:
- The oxidation number of hydrogen is generally +1.

2. **Set up the equation**:
- Let the oxidation number of nitrogen be \( x \).
- In the compound \( N_2H_5^+ \), there are 2 nitrogen atoms and 5 hydrogen atoms.
- The overall charge of the ion is +1.

3. **Write the equation based on the oxidation states**:
- The equation can be set up as follows:
\[ 2x + 5(+1) = +1 \]

4. **Simplify the equation**:
- This simplifies to:
\[ 2x + 5 = +1 \]

5. **Solve for \( x \)**:
- Rearranging the equation gives:
\[ 2x = +1 - 5 \]
\[ 2x = -4 \]
\[ x = -2 \]

6. **Conclusion**:
- Therefore, the oxidation number of nitrogen in \( N_2H_5^+ \) is \( -2 \).

### Final Answer:
The oxidation number of nitrogen (N) in \( N_2H_5^+ \) is \( -2 \).