If a gas at a pressure of `10 atm` at `300 K` expands against a constant external pressure of `2 atm` from a vol. `10` litres to `20` litres find work done ? [Isothermal process]

Explanation

To solve the problem of calculating the work done by the gas during its expansion, we can follow these steps:

### Step 1: Identify the Given Data
- Initial pressure of the gas, \( P_{\text{gas}} = 10 \, \text{atm} \) (not needed for work calculation)
- External pressure, \( P_{\text{external}} = 2 \, \text{atm} \)
- Initial volume, \( V_1 = 10 \, \text{litres} \)
- Final volume, \( V_2 = 20 \, \text{litres} \)

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