A liquid of volume of `100 L` and at the external pressure of `10 atm-Lt` the liquid is confined inside an adiabatic bath. External pressure of the liquid is suddenly increased to `100 atm` and the liquid gets compressed by `1 L` against this pressure then find,
(i) Work (ii) `Delta U` (iii) `Delta H`

Explanation

To solve the problem step by step, we will calculate the work done, the change in internal energy (ΔU), and the change in enthalpy (ΔH) for the given adiabatic process.

### Given Data:
- Initial Volume (V1) = 100 L
- Final Volume (V2) = 100 L - 1 L = 99 L
- Initial Pressure (P1) = 10 atm
- Final Pressure (P2) = 100 atm
- Process Type: Adiabatic (Q = 0)
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