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Calculate the number of kJ of heat neces...

Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from `35^(@)C "to" 55^(@)C.` Molar heat capacity of Al is 24 J `mol^(-1) K^(-1)`.

Text Solution

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Given Mass of `Al=60.0g`
Molar heat capacity of `Al=24 mol^(-1)K^(-1)`
rise in temp `= Delta T=(55-35)=20.0^(@)C`
Asked Heat required in `KJ`
Formula Heat `=nC Delta T`
Explanation `n=` mole of `Al`
`C=` molar heat capacity
`Delta T=` Temperature difference
`ul("Calculation of mole of" Al)=(60.0)/(27)2.22`
Substitution & Calculation
`:.` Total hear required `=(60.0)/(27)xx20.0xx24.0J`
`=1066 J= 1.06 KJ`.
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