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An ideal gas can be expended from an ini...

An ideal gas can be expended from an initial state to a certain volume through two different processes
(i) `pV^(2)=` constant and (ii) `p=KV^(2)` where K is a positive constant. Then

A

Final temperature in (i) will be greater then in (ii)

B

Final temperature in (ii) will be greater then in (i)

C

Total heat given to the gas in (i) case is greater than in (ii)

D

Total heat given to the gas in (ii) case is greater than in (i)

Text Solution

Verified by Experts

The correct Answer is:
B, D
From equation `PV=nRT`
`P_(c ) lt P_(B),V_(c)=V_(B)` and `T_(B) gt T_(c )`
`W_(AB) gt W_(AC) (T_(B)-T_(A)) gt T_(c )-T_(A)`
So By `1st` law
`Q=Delta U+W`
`Q=(f_(i))/(2)nR Delta T+W " " Q_(AB) gt Q_(AC)`
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