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For the reaction 2CO +O(2) rarr 2CO(2)...

For the reaction
`2CO +O_(2) rarr 2CO_(2), DeltaH =- 560 kJ`,
`2mol` of `CO` and `1mol` of `O_(2)` are taken in a container of volume `1L`. They completely form `2 mol` of `CO_(2)`. If the pressure in the vessel changes from `70` to `40atm`, find the magnetic (absolute) value of `DeltaU at 500K. (1 L-atm = 0.1 kJ)`

Text Solution

Verified by Experts

The correct Answer is:
`Delta H= Delta U+ Delta (PV)`
so, `Delta U=Delta H-Delta (PV)= -560-[40-70] (L atm)= (-560 + 30xx0.1)kJ= -557 kJ`.
`Delta H=Delta U+Delta (PV)`
so, `Delta U=Delta H-Delta (PV)= -560-[40-70](Latm)=(-560+30xx0.1)KJ= -557KJ`
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