Home
Class 12
CHEMISTRY
For the equilibrium, PCI(5)(g) hArr PC...

For the equilibrium,
`PCI_(5)(g) hArr PCI_(3)(g) +CI_(2)(g) at 25^(@)C K_(c) =1.8 xx 10^(-7)`
Calculate `DeltaG^(Theta)` for the reaction `(R = 8.314 J K^(-1) mol^(-1))`.

Text Solution

Verified by Experts

The correct Answer is:
`DeltaG^(@)` of reaction is 38457 J/mol
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    RESONANCE ENGLISH|Exercise exercise-3 Part-3 :(Only one option correct type) section A|8 Videos
  • THERMODYNAMICS

    RESONANCE ENGLISH|Exercise exercise-3 Part-3 :(Only one option correct type) section B|12 Videos
  • THERMODYNAMICS

    RESONANCE ENGLISH|Exercise exercise-3 Part-3 :(Subjective questions)Section B|8 Videos
  • TEST SERIES

    RESONANCE ENGLISH|Exercise CHEMISTRY|50 Videos

Similar Questions

Explore conceptually related problems

For the chemical equilibrium PCl_(5)(g) hArr PCl_(3)(g) +Cl_(2) (g) " at " 298K, K_(c )=1.8xx10^(-7) . Calculate Delta_(r )G^(Theta) for the forward reaction R=8.31JK^(-1)"mol"^(-1)

Vapour density of equilibrium PCI_(5)(g)hArrPCI_(3)(g)+CI_(2)(g) is decreased by

For the equilibrium reaction: 2H_(2)(g) +O_(2)(g) hArr 2H_(2)O(l) at 298 K DeltaG^(Theta) = - 474.78 kJ mol^(-1) . Calculate log K for it. (R = 8.314 J K^(-1)mol^(-1)) .

For PCI_5(g) hArr PCI_3(g) +CI_2(g) , write the expression of K_c .

The equilibrium constant for the reaction CO_(2)(g) +H_(2)(g) hArr CO(g) +H_(2)O(g) at 298 K is 73 . Calculate the value of the standard free enegry change (R =8.314 J K^(-1)mol^(-1))

The equilibrium constant for the reaction CO_(2)(g) +H_(2)(g) hArr CO(g) +H_(2)O(g) at 298 K is 73 . Calculate the value of the standard free enegry change (R =8.314 J K^(-1)mol^(-1))

For a reaction, K_p = 1.8 xx 10^(-7) at 300K. What is the value of DeltaG^@ at this temeprature ? (R =8.314 J K^(-1) mol^(-1))

The equilibrium constant at 25^(@)C for the process: CO^(3+) (aq) +6NH_(3)(aq) hArr[Co(NH_(3))_(6)]^(3+)(aq) is 2 xx 10^(7) . Calculate the value of DeltaG^(Theta) at 25^(@)C at 25^(@)C[R = 8.314 J K^(-1)mol^(-1)] . In which direction the reaction is spontaneous when the recatants and proudcts are in standard state?

The equilibrium constant at 25^(@)C for the process: CO^(3+) (aq) +6NH_(3)(aq) hArr[Co(NH_(3))_(6)]^(3+)(aq) is 2 xx 10^(7) . Calculate the value of DeltaG^(Theta) at 25^(@)C at 25^(@)C[R = 8.314 J K^(-1)mol^(-1)] . In which direction the reaction is spontaneous when the recatants and proudcts are in standard state?

For the reaction PCl_(3)(g)+Cl_(2)(g)rarrPCl_(5)(g),K_(c) is 26 at 250^(@)C . K_(p) at the same temperature is (R=8.314JK^(-1)mol^(-1))