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For a particular reversible reaction at ...

For a particular reversible reaction at temperature `T, DeltaH` and `DeltaS` were found to be both `+ve`. If `T_e` is the temperature at equilibrium, the reaction would be spontaneous when :

A

`T_(e) gt T`

B

`T gt T_(e)`

C

`T_(e)` is 5 times T

D

`T=T_(e)`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaG=DeltaH -TDeltaS`
For spontaneous reaction `DeltaG` must be negative ltbRgt At equilibrium temperature `DeltaG=0`
to maintain the negative value of `DeltaG`
T should be greater than `T_(circ)`
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