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The entropy change involved in the isoth...

The entropy change involved in the isothermal reversible expansion of 2 moles of an ideal gas from a volume of 10 dm3 a volume of 100 dm3 at `27^@C` is

A

`38.3 J mol^(-1) K^(-1)`

B

`35.8 J mol^(-1) K^(-1)`

C

`32.3 J mol^(-1) K^(-1)`

D

`42.3 J mol^(-1) K^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

`DeltaS=nR In (V_(2))/(V_(1))=2.303 "nR log" (V_(2))/(V_(1)) = 2.303 xx 2 xx 8.314 xx "log"(100)/(10) = 38.3 Jmol^(-1) K^(-1)`
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