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Given : NO(3)^(-) rarrNO(2)( acidic me...

Given `:`
`NO_(3)^(-) rarrNO_(2)(` acidic medium `), " "E^(-)=0.8V`
`NO_(3)^(-) rarr NO_(3)OH(` acidic medium`)" "E^(-)=0.74V`
At what `pH` the above two half reactions will have same `EMF` values ? Assume the concentration of all the species to be unity. `(` Take `0.059~~0.06)`

Text Solution

Verified by Experts

The correct Answer is:
`pH=1.5`

`overset(+5)(N)O_(3)^(-)+2H^(+)+e^(-)tooverset(+4)(N)O_(2)+H_(3)O,0.79"volt"`
`overset(+5)(N)O_(3)^(-)+8H^(+)+6e^(-)toNH_(3)OH^(+)+2H_(2)O,0.731"volt"`
`E=0.79-(0.0591)/(1)log((1)/([H^(+)]^(2)))=0.731-(0.591)/(6)log((1)/([H^(+)]^(8)))`
`0.059=0.059(2-(8)/(6))pHimpliespH=(6)/(4)=1.5`
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