Home
Class 12
CHEMISTRY
A certain metal salt solution is electro...

A certain metal salt solution is electrolysed in series with a silver coulometer. The weight of silver and the metal deposited are `0.5094g` and `0.2653g`. Calculate the valency of the metal if its atomic weight is nearly that of silver.

Text Solution

Verified by Experts

The correct Answer is:
2

`(W_(Ag))/(W_("metal"))=(E_(Ag))/(E_(M))=(108)/((108)/(n))=n`
`n=(0.5094)/(0.2653)=1.92`
`n=2`.
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISRY

    RESONANCE ENGLISH|Exercise Assertion Reasoning|11 Videos
  • ELECTROCHEMISRY

    RESONANCE ENGLISH|Exercise Subjective Questions|14 Videos
  • ELECTROCHEMISRY

    RESONANCE ENGLISH|Exercise Board Level Exercise|20 Videos
  • ELECTRO CHEMISTRY

    RESONANCE ENGLISH|Exercise PHYSICAL CHEMITRY (ELECTROCHEMISTRY)|53 Videos
  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE ENGLISH|Exercise Part -IV|22 Videos

Similar Questions

Explore conceptually related problems

3.0 g of metal chloride gave 2.0 g of metal. Calculate the equivalent weight of the metal.

1.0 g of a metal oxide gave 0.2 g of metal. Calculate the equivalent weight of the metal.

Which solution is used for the leaching of silver metal in the presence of air in the metallurgy of silver ?

0.452 g of a metal nitrate gave 0.4378 g of its metal sulphate. Calculate the equivalent weight of the metal.

1.0 g of metal nitrate gave 0.86 g of metal sulphate. Calculate the equivalent weight of metal.

The same current if passed through solution of silver nitrate and cupric salt connected in series. If the weights of silver deposited is 1.08g . Calculate the weight of copper deposited

0*3605 g of a metal is deposited on the electrode by passing 1*2 amperes of current for 15 minutes through its salt solution. The atomic weight of the metal is 96. What is the valency of the metal ?

1.0 g of metal nitrate gave 0.86 g of metal carbonate. Calculate the Equivalent weight of metal.

0.76 g of a silver salt of a dibasic acid on ignition gave 0.54 g of silver. Calculate the molecular mass of the acid.

A current of 3 amperes was passed through silver nitrate solution for 125 seconds. The amount of silver deposited at cathode was 0.42 g. Calculate the equivalent mass of silver.

RESONANCE ENGLISH-ELECTROCHEMISRY-Exercise
  1. Find the number of electrons involved in the electro-deposition of 63....

    Text Solution

    |

  2. A current 0.5 ampere when passed through AgNO(3) solution for 193 sec....

    Text Solution

    |

  3. A certain metal salt solution is electrolysed in series with a silver ...

    Text Solution

    |

  4. 3A current was passed through an aqueous solution of an unknown salt o...

    Text Solution

    |

  5. How long a current of 2 A has to be passed through a solution of AgNO(...

    Text Solution

    |

  6. A metal is know to form fluoride MF(2). When 10A of electricity is pas...

    Text Solution

    |

  7. A certain electricity deposited 0.54g of Ag from AgNO(3) solution what...

    Text Solution

    |

  8. A current of 3.6A is a passed for 6 hrs between Pt electrodes in 0.5L ...

    Text Solution

    |

  9. Find the volume of gases evolved by passing 0.9655. A current for 1 hr...

    Text Solution

    |

  10. Cd amalgam is preapred by electrolysis of a solution CdCI(2) using a ...

    Text Solution

    |

  11. Electrolysis of a solution of HSO(4)^(-) ions produces S(2)O(8)^(-). A...

    Text Solution

    |

  12. One of the methods of preparation of per disulphuric acid, H(2)S(2)O(8...

    Text Solution

    |

  13. The Standard reduction potential of E(Br^(3+)+Bi)^(@) "and" E(Cu^(2+)/...

    Text Solution

    |

  14. A fuel cell uses CH4(g) and forms CO(3)^(2-) at the anode.It is used t...

    Text Solution

    |

  15. The resistance of a N//10 KCI solution is 245 ohms. Calculate the spec...

    Text Solution

    |

  16. The resistance of a solution 'A' is 50 ohm and that of solution 'B' is...

    Text Solution

    |

  17. In a conductivity cell the two platinum electrodes each of area 10 sq....

    Text Solution

    |

  18. The equivalent conductance of 0.10 N solution of MgCI(2) is 97.1 mho c...

    Text Solution

    |

  19. The specific conductance of a N//10 KCI solution at 18^(@)C is 1.12 xx...

    Text Solution

    |

  20. The equivalent conductances of an infinitely dilute solution NH(4)CI i...

    Text Solution

    |