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A metal is know to form fluoride MF(2). ...

A metal is know to form fluoride `MF_(2)`. When `10A` of electricity is passed through a molten sat for `330sec, 1.95g` of metal is deposited. Find the atomic weight of M. what will be the quantity electricity required to deposit the same mass of `Cu` form `CuSO_(4)`?

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The correct Answer is:
`A=114,Q=5926.8C`.
v.f. of metal `=2`
`w=Zit`
`1.96=(E)/(96500)` it `=(Mxxit)/(v.f.xx96500)impliesM=114gm`.
Now for `Cu` `W=(63.5xx(it))/(2xx96500)implies1.95=(63.5(it))/(2xx96500)impliesit=5926.77C`
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