One of the methods of preparation of per disulphuric acid, `H_(2)S_(2)O_(8)`, involve electrolytic oxidation of `H_(2)SO_(4)` at anode `(2H_(2)SO_(4) rarr H_(2)S_(2)O_(8)+2H^(+) +2e^(-))` with oxygen and hydrogen as by-products. In such an electrolysis, `9.722L` of `H_(2)` and `2.35L` of `O_(2)` were generated at STP. what is the weight of `H_(2)S_(2)O_(8)` formed?

Answer

`43.456g`

Explanation

Reaction at anode `2H_(2)SO_(4)toH_(2)S_(2)O_(8)+2H^(+)+2e^(-)`
`H_(2)S_(2)O_(8),O_(2)` are the product at anode.
`2H_(2)OtoO_(2)+4H^(+)+4e^(-)`
Reaction at cathode `2H_(2)O+2e^(-)toH_(2)+2OH^(-)` ltbr. Eq. of `H_(2)="Eq. of " O_(2)+"Eq. of " H_(2)S_(2)O_(8)`
`(9.722)/(22.4)xx2=(2.35)/(22.4)xx4+x xx2impliesx=0.244"mole" impliesW_(H_(2)S_(2)O_(8))=43.49g`