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A fuel cell uses CH4(g) and forms CO(3)^...

A fuel cell uses `CH_4(g)` and forms `CO_(3)^(2-)` at the anode.It is used to power a car with 80 Amp.for 0.96 hr.How many litres of `CH_(4)(g)` (at STP.) would be required ? `(V_m=22.4 L//mol)(F=96500)`.Assume 100% efficiency.

Text Solution

Verified by Experts

The correct Answer is:
`8`

`CH_(4)+10OH^(-)toCO_(3)^(2-)+7H_(2)O+8e^(-)`
No. of faradays required`=(80xx3600xx0.96)/(96500)`
`V_(CH_(4))=(1)/(8)xx(80xx3600xx0.96)/(96500)xx22.4L=8356xx0.96=8.02L`
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