The resistance of a solution 'A' is 50 ohm and that of solution 'B' is 100 ohm, both solution being taken in the same conductivity cell. If equal volumes of solution A and B are mixed, what will be the resistance of the mixture using the same cell. (Assume that there is no increase in the degree of dissociation of A and B on mixing)

Answer

`R=66.67ohms`

Explanation

`R_(A)=500Omega, R_(B)=100Omega`
`K_(A)=(1)/(50)xx(l)/(A) & K_(B)=(1)/(100)xx(l)/(A)`
When equal volumes one taken the
`K_("resultant")=(1)/(R^(1))x(2l)/(A)=(1)/(50)xx(l)/(A)+(1)/(100)xx(l)/(A)`
`(2)/(R^(1))=(150)/(50xx100)impliesR^(1)=(2xx50xx100)/(150)=(200)/(3)=66.7Omega`