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E^(@) for F(2)+2e^(-) hArr 2F^(-) is 2.8...

`E^(@)` for `F_(2)+2e^(-) hArr 2F^(-)` is `2.8V,E^(@)` for
`(1)/(2)F+e^(-)=F^(-)` is `-`

A

2.8 V

B

1.4 V

C

`-2.8 V`

D

`-1.4V`

Text Solution

Verified by Experts

The correct Answer is:
A
`E^(0)` is intensive property and it does not depend on mass of `F_(2)` taking part.
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