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The potential of the Daniel cell, Zn |{:...

The potential of the Daniel cell, `Zn |{:(ZnSO_(4)),((1M)):}||{:(CuSO_(4)),((1M)):}|Cu` was reported by Buckbse,Surdzial and Metz as `E^(@) = 1.1028 - 0.641 xx 10^(-3)T +0.72 xx 10^(-5)T^(2)`, where `T` is the celsius temperature. Calculate `DeltaS^(@)` for the cell reaction at `25^(@)C`/

A

`-45.32EU`

B

`-34.52EU`

C

`-25.43EU`

D

`-54.23EU`

Text Solution

Verified by Experts

The correct Answer is:
D
`E^(@)=1.1028-0.641xx10^(-3)T+0.72xx10^(-5)T^(2)`
`((dE^(@))/(dT))_(2S)=-0.641xx10^(-3)+2xx0.72xx10^(-5)T=(-0.641+0.36)xx10^(-3)=-0.281xx10^(-3)`
`triangleS^(@)=nF(dE)/(dT)=2xx96500xx(-281xx10^(3))=-54.23EU`
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