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A current of 9.65 ampere is passed throu...

A current of `9.65` ampere is passed through the aqueous solution `NaCI` using suitable electrodes for `1000s`. The amount of `NaOH` formed during electrolysis is

A

2.0 g

B

4.0 g

C

6.0 g

D

8.0 g

Text Solution

Verified by Experts

The correct Answer is:
B
`2H_(2)O+2e^(-)toH_(2)+2OH^(-)`
No. of faraday passed `=(9.65xx1000)/(96500)=0.1F`
`n_(OH^(-))` formed `=0.1` mol
`nNaOH=0.1` mol `-=4gm`
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