If 0.224 L of H(2)(g) is formed at the c...

If `0.224 L` of `H_(2)(g)` is formed at the cathode of one cell at `STP,` how much of `Mg` is formed at the cathode of the other electrolytic cell arranged in series ?

0.224 L

0.448 L

0.112 L

1.12L

Text Solution

Verified by Experts

The correct Answer is:

Equivalent of `H_(2)=` equivalence of `O_(2)`
`(0.224)/(22.4)xx2=("volume of "O_(2))/(22.4)xx4`
`0.112` litre `="volume of " O_(2)`

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