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The ionization constant of a weak monoba...

The ionization constant of a weak monobasic acid is `25xx10^(-6)` while the equivalent conductance of its 0.01 M solution is `"19.6 Scm"^(2)eq^(-1)`. The equivalent conductance of the electrolyte at infinite dilution `("in Scm"^(2)"eq"^(-1))` will be

A

250

B

196

C

392

D

384

Text Solution

Verified by Experts

The correct Answer is:
C
`Ka=25xx10^(-6)^^_(eq)=19.6Scm^(2)eq^(-1),C=0.01`
`Ka=0.01xxalpha^(2)impliesalpha=sqrt((25xx10^(-6))/(10^(-2)))=5xx10^(-2)`
`alpha=5xx10^(-2)=(19.6)/(^^_(eq)^(@))implies^^_(eq)^(@)=(19.6)/(5xx10^(-2))=392Scm^(2)eq^(-1)`
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