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The specific conductivity of a saturated...

The specific conductivity of a saturated solution of AgCl is `3.40xx10^(-6) Omega^(-1)cm^(-1)` at `25^(@)C`. If `lambda_(Ag)=62.3Omega^(-1)cm^(2)"mol"^(-1)` and
`lambda_(Cl^(-))=67.7 Omega^(-1) cm^(2)"mol"^(-1)`, the solubility of AgCl at `25^(@)C` is :-

A

`2.6xx10^(-5)M`

B

`4.5xx10^(-3)M`

C

`3.6xx10^(-5)M`

D

`3.6xx10^(-3)M`

Text Solution

Verified by Experts

The correct Answer is:
A
`lamda_(Ag^(+))=62.3Scm^(2)mol^(-1),lamda_(cl^(-))=67.7Scm^(2)"mole"^(-1)`
`K_(Agd)=3.4xx10^(-6)Scm^(-1)`
`^^_(AgCl)^(infty)=(62.3+67.5)=(1000xx3.4xx10^(-6))/(S)`
`S=(3.4xx10^(-3))/("normality")`
Normality`=2xx10^(-3)M`
molarity`=(2xx10^(-3))/(2)=10^(-3)M`
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