The specific conductance of a 0.01 M solution of acetic acid at 298K is `1.65xx10^(-4)ohm^(-1)cm^(-1)`. The molar conductance at infinite dilution fo `H^(+)` ion and `CH_(3)COO^(-)` ion are 349.1 `ohm^(-1)cm^(2)mol^(-1)` and `40.9ohm^(-1)cm^(2)mol^(-1)` respectively.
Calculate :
Molar conductance of the solution.

Options

A. `1.4xx10^(-5)molL^(-1)`
B. `1xx10^(-2)molL^(-1)`
C. `1xx10^(-5)molL^(-1)`
D. `1.9xx10^(-5)molL^(-1)`

Answer

C

Explanation

`K=1.382xx10^(-6)scm^(-1)`
`^^_(AgCl)=61.9+76.3=138.2=(1000xx1.382xx10^(-6))/(S)`
`S=10^(-5)M`.