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Find the equilibrium constant for the re...

Find the equilibrium constant for the reaction
`Cu^(2+)+ 1n^(2+) Cu^(+) + 1n^(3+)`
Given that `E_(CU^(2+)//CU^(+))^(@) = 0.15V, E_(In^(2+)//1n^(+)) = -0.4V`
`E_(1n^(3+)//1n^(+))^(@) = - 0.42V`

Text Solution

Verified by Experts

The correct Answer is:
`K_(C)=10^(10)`
`ln^(+)toln^(3+)+2e^(-)" "0.42"volt"`
`underline(ln^(2+)+etoln^(+))" "-0.4"volt"`
`underline(ln^(2+)toln^(3+)+e^(-))`
`E^(@)=0.44"volt"`
`E_(cell)^(@)=0.15+0.44=0.59"volt"`
`0=0.59-(0.059)/(2)logK.`
`K=10^(10)`
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