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What is the standard reduction potential...

What is the standard reduction potential `(E^(@))` for `Fe^(3+) to Fe`?
Given that :
`Fe^(2+) + 2e^(-) to Fe, E_(Fe^(2+)//Fe)^(@)`=-0.47V
`Fe^(3+) + e^(-) to Fe^(2+), E_(Fe^(3+)//Fe^(2+))^(@) = +0.77V`

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Bacause standard electrode potential `Ti^(4+)//Ti^(3+)` is less than of `Fe^(3+)//Fe^(2+)` so it cannot oxides `Fe^(II)` to `Fe^(III)`
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What is the standard reducing potential (E^(@)) for Fe^(3+)to Fe ? (Given that Fe^(2+)+2e^(-)rightarrowFe, E_(Fe^(2+)//Fe^(@)) =-0.47V Fe^(3+) + e^(-)to Fe^(2+) , E_(Fe^(3+)//Fe^(2+))^(@)= +0.77V

Given that the standard reduction potentials E ^(0) of Fe^(+2)|Feis 0.26V and Fe ^(+3) |Fe is 0.76V respectively. The E ^(@)of Fe ^(+2)|Fe^(+3) is:

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Given that E_(Fe^(2+)//Fe)^(.)=-0.44V,E_(Fe^(3+)//Fe^(2+))^(@)=0.77V if Fe^(2+),Fe^(3+) and Fe solid are kept together then

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The standard reduction potentials at 298K for the following half cells are given : ZN^(2+)(aq)+ 2e^(-)Zn(s) , E^(@) = - 0.762V Cr^(3+)(aq)+ 3e^(-) Cr(s) , E^(@) = - 0.740V 2H^(+) (aq)+2e^(-) H_(2)(g) , E^(@)= 0.000V Fe^(3+)(aq)+ e^(-) Fe^(2+)(aq) , E^(@) = 0.770V which is the strongest reducing agent ?

(i) On the basis of the standard electrode potential values stated for acid solutions, predict whether Ti^(4+) species may be used to oxidise Fe(II) to Fe(III) {:(Ti^(4+) + e^(-) to Ti^(3+), E^(@) = +0.01V), (Fe^(3+) + e^(-) to Fe^(2+), E^(@)= +0.77V):} (ii) Based on the data arrange Fe^(3+), Mn^(2+) " and " Cr^(2+) in the increasing order of stability of +2 oxidation state. (Give a brief reason) E_(Cr^(3+)//Cr^(2+))^(@) = -0.4V E_(Mn^(3+)//Mn^(2+))^(@) = +1.5V E_(Fe^(3+)//Fe^(2+))^(@) = +0.8V

At equimolar concentration of Fe^(2+) and Fe^(3+) , what must [Ag^(+)] be so that the voltage of the galvanic cell made from the (Ag^(+) | Ag) and (Fe^(3+)|Fe^(2+) electrodes equals zero? Fe^(2+) + Ag^(+) rightarrow Fe^(3+) + Ag E_(Ag^(+), Ag)^(@) = 0.7991, E_(Fe^(3+)//Fe^(2+))^(@) = 0.771

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