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Pt |{:((H(2))),(1atm):}:| pH = 2:|:|:pH ...

`Pt |{:((H_(2))),(1atm):}:| pH = 2:|:|:pH =3 |:{:((H_(2))Pt),(1atm):}:|`. The cell reaction for the given cell is:-

A

spontaneous

B

non-spontaneous

C

Equilibrium

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(cell)=E_(cell)^(0)-(0.0591)/(1)log_(10)(([H^(+)]_(anode))/([H^(+)]_(cathode)))=-(0.0591)/(1)log_(10)((10^(-2))/(10^(-3)))=-ve` (non spontaneous).
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