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Calculate the cell EMF is mV for Pt|H(...

Calculate the cell EMF is mV for
Pt|`H_(2)`(1 atm)|HCl(0.01M)|AgCl(s)|Ag(s) at 298 K
if `DeltaG_(f)^(@)` values are at `25^(@)C`
`-109.56(kJ)//(mol)` for AgCl(s) and
-130.79`(kJ)//(mol)` for `(H^(+)+Cl^(-))` (aq)

A

`456mV`

B

`654mV`

C

`546mV`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`triangleG_("cell reaction")^(0)=2(-130.79)-2(-109.56)=-42.46kJ//"mole"`
(for `H_(2)+2AgClto2Ag+2H^(+)+2Cl^(-))`
`thereforeE_(cell)^(0)=(-42460)/(-2xx96500)=+0.220V`
Now `E_(cell)=+0.220+(0.059)/(2)log((1)/((0.01)^(4)))=0.456V=456mV`.
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