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After electrlysis of NaCI solution with ...

After electrlysis of `NaCI` solution with inert electrodes for a certain period of time `600mL` of the solution was left. Which was found to be `1N` in `NaOH`. During the same time, `31.75 g` of `Cu` deposited in the copper voltameter in series the electrolytic cell. calculate the percentage yield of `NaOH` obtained.

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The correct Answer is:
`60%`
Equivalent of Cu deposited `=(31.75xx2)/(63.5)=1`
equivalent of NaOH formed `=0.6xx0.6`
`%` yield of `NaOH=60%`
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