Home
Class 12
CHEMISTRY
A 1 cm xx 1 cm square paper coated with ...

A `1 cm xx 1 cm` square paper coated with a suitable adsorbent on both sides. The paper is dipped in a aqueous solution of glucose of volume 20 mL and concentration 20 ppm. Final concentration glucose was dropped to 19 ppm due to adsorption. Find the number of glucose particles per unit area of the paper.

Text Solution

Verified by Experts

The correct Answer is:
Mass of glucose adsorbed `=(20-19)xx20/10^(6)=2xx10^(-5) g`
Moles of glucose adsorbed `=(2xx10^(-5))/180=10^(-6)/9`
Number of glucose molecules `=10^(-6)/9xx6xx10^(23)=20/3xx10^(16)`
Number of glucose molecules per unit area`=1/2xx20/3xx10^(16)=3.33xx10^(16) cm^(-2)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

Two glucose solution are mixed. One has a volume of 480 mL and a c oncentration of 1.50 M and the second has a volume of 250 mL and concentration 1.20 M . The molarity of final solution is

20 mg of K^(o+) ions are present in 1 L of aqueous solution. Density of the solution is 0.8 mL^(-1) . What is the concentration of K^(o+) ions in ppm?

In a tyre of "Ferrari" car of Mr. Obama, a tube having a volume of 12.3 litres is filled with air at a pressure of 4 atm at 300 K.Due to travelling, the temperature of the tube and air inside it raised to 360 K and pressure reduced to 3.6 atm in 20 minutes. If the porosity (number of pores per unit area) of the tube material is 5xx10^3 pores/ cm^2 and each pore can transfer air from inside to outside of the tube with the rate of 6.023xx10^8 molecules per minute.Calculate the total surface area (m^2) of the tube.(R=0.082 Lt-atm/mole-K) Give your answer divide by 100.

A tube of uniform cross-sectional area 1 cm^(2) is closed at one end with semi-permeable membrane. A solution of 5 g glucose per 100 mL is placed inside the tube and is dipped in pure water at 27^(@)C . When equilibrium is established, calculate: a. The osmotic pressure of solution. b.The height developed in vertical column. Assume the density of final glucose solution 1 g mL^(-1)

A tube of uniform cross sectional area 1cm^(-2) is closed at one end with semi permeable mebrane. A solution having 5 gm glucose per glucose per 100 ml is placed inside the tube and dipped in pure water at 27^(@)C . When the equilibrium is established. what will be the osmotic pressure height developed in vertical column. Also caiculate molality and molarity of the solution Density of glucose is 1gm/ml.

The time required to coat aluminum metal on the surface of a square plate of length 20 cm about 5 mm thickness on both sides by using molten AlCl_3 solution and 10 A current is nearly [Specific gravity of Al = 1.8 g mL^(-1) ]

Around 20% surface sites have adsorbed N_(2) . On heating N_(2) gas evolved form sites and were collected at 0.001 atm and 298 K in a container of volume 2.46cm^(3) the density of surface sites is 6.023xx10^(14)cm^(-2) and surface area is 1000cm^(2) find out the number of surface sites occupied per molecule of N_(2) .

Around 20% surface sites have adsorbed N_(2) . On heating N_(2) gas evolved form sites and were collected at 0.001 atm and 298 K in a container of volume 2.46cm^(3) the density of surface sites is 6.023xx10^(14)cm^(-2) and surface area is 1000cm^(2) find out the number of surface sites occupied per molecule of N_(2) .

Use graph paper for this equation. Draw the graph of 3x-2y=5 and 2x=3y on the same axes. Use 2cm =1 unit on the both the axes and plot only 2 points per line. Write down the co-ordinates of the point of intersection of the two lines. Also find the area of the triangle formed by the lines and the y-axis.

This interference film is used to measure the thickness of slides, paper, etc. The arrangement is as shown in fig. For the sake of clarity, the two strips are shown thick. Consider the wedge formed in between strips 1 and 2. If the interference pattern because of the two waves reflected from wedge surface is observed, then from the observed data we can compute thickness of paper, refractive index of the medium filled in wedge, number of bonds formed, etc. Considre the strips to be thick as compared to wavelength of ligth and light is incident normally. Neglect the effect due to reflection from top surface of strip 1 and bottom surface of strip 2. Take L = 5 cm and lambda_(air) = 40 nm . Consider an air wedge formed by two glass plates. having refractive index 1.5 by placing a piece of paper of thickness 20 mm. Determine the number of dark bands formed.