Home
Class 12
CHEMISTRY
Graph between log""x/m and log P is a s...

Graph between `log""x/m` and log P is a straight line inclined at an angle `Cl_4`When pressure is 0.5 atm and log k=0.699, the amount of solute adsorbed per g of adsorbent will be:

A

`1`

B

`1.5`

C

`0.25`

D

`2.5`

Text Solution

Verified by Experts

The correct Answer is:
A

logx/M=log K+1/n log P`
`1/n=tan 45^(@)" "ln k=0.69`
`n=1" "k=2`
`x/m=2xx(0.5)^(1)`
`x=1`
Promotional Banner

Similar Questions

Explore conceptually related problems

Graph between log x//m and log p is a straight line inclined at an angle of 45^@ . When pressure is 0.5 atm and 1n k = 0.693 , the amount of solute adsorbed per gram of adsorbent will be:

Plot of log(x/m) against log P is a straight line inclined at an angle of 45^(@) . When the pressure is 0.5 atm and Freundlich parameter ,K is 10, the amount of solute adsorbed per gram of adsorbent will be : (log 5=0.6990 )

Plot of log against log P is a straight line inclined at an angle of 45^(@) . When the pressure is 0.5 atm and Freundlich parameter ,K is 10, the amount of solute adsorbed per gram of adsorbent will be : (log 5=0.6990 )

Graph between log x/m and log P is a straight line at angle of 45^(@) with intercept 0.4771 on y-axis. Calculate the amount of gas adsorbed in gram per gram of adsorbent when pressure is 3 atm.

The graph between log k versus 1//T is a straight line.

When a graph is plotted between log x/m and log p, it is straight line with an angle 45^@ and intercept 0.6020 on y-axis.if initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gram of adsorbent :

When a graph is plotted between log x//m and log p, it is straight line with an angle 45^(@) and intercept 0.3010 on y- axis . If initial pressure is 0.3 atm, what wil be the amount of gas adsorbed per gm of adsorbent :

For freundlich adsorption isotherm, a plot of log ( x/m) ( y - axis ) and log p (x-axis) gives a straight line . The intercept and slope for the line is 0.4771 and 2, respectively . The mass of gas , adsorbed per gram of adsorbent if the intital pressure is 0.04 atm , is ________ xx 10^(-4) g. (log 3=0.4771).

Graph between log((x)/(m)) and log P is straight line at angle of 45^(@) with the intercept of 0.6020. The extent of adsorption ((x)/(m)) at a pressure of 1 atm is

Adsorption of a gas on a surface follows Freundlich adsorption isotherm. Plot of "log " (x)/(m) versus log P gives a straight line with slope equal to 0.5, then : ( (x)/(m) is the mass of the gas adsorbed per gram of adsorbent)