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The value of KP for the reactions N2(g)...

The value of `K_P` for the reactions `N_2(g) +3H_2(g) hArr 2NH_3(g), " is " 4.28 xx 10 ^(-5) " at " 450 ^(@) C`. A reaction mixture contains `N_2,H_2 and NH_3` at partial pressures of 0.6 atm ,2.5 atm and 0.50 atm respectively . In which direction the reaction will proceed?

Text Solution

Verified by Experts

`Q_(P)=([P_(Br_(2))]^(1//2)[P_(NO)])/([P_(NOBr]])=([0.2]^(1//2)[0.4])/([0.50])=0.36`
`K_(P)=0.15`
`therefore Q_(P)gtK_(P)`
Hence, reaction will shift in backward direction `therefore Br_(2)` will be consumed
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