Home
Class 11
CHEMISTRY
Consider the following equilibrium in a ...

Consider the following equilibrium in a closed container,
`N_(2)O_(4(g))hArr2NO_(2(g))`
At a fixed temperature, the volume of the reaction container is halved. For this change which of the following statements holds true regarding the equilibrium constant `(K_(p))` and degree of dissociation `(alpha)`?

A

neither `K_(P)` nor `alpha` changes

B

both `K_(P)` and `alpha` change

C

`K_(P)` changes, but `alpha ` does not change

D

`K_(P)` does not change but `alpha ` changes

Text Solution

Verified by Experts

The correct Answer is:
D

`N_(2)O_(4)(g)hArr2NO_(2)`.
`{:("moles"t=0,1,0),("moles at eq.",1-alpha,2alpha):}`
`K_(P)=((2alpha)/((1+alpha))xxP)^(2)/((1-alpha)/(1+alpha)xxP)=(4alpha^(2))/(1-alpha^(2))xxP`.
When volume is halved, `P` is double.
`therefore alpha` will change a `K_(P)` is independent of pressure change.
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Exercise-3 (Part-2)|17 Videos
  • CHEMICAL EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Advanced Level Problems (Part-1)|31 Videos
  • CHEMICAL EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Exercise-2 (Part-4)|6 Videos
  • CHEMICAL BONDING

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Fundamental Concept )|6 Videos
  • D & F-BLOCK ELEMENTS & THEIR IMPORTANT COMPOUNDS

    RESONANCE ENGLISH|Exercise Match the column|1 Videos

Similar Questions

Explore conceptually related problems

Consider the following equilibrium in a closed container: N_(2)O_(4)(g)hArr2NO_(2)(g) At a fixed temperature, the volume of the reaction container is halved. For this change which of the following statements holds true regarding the equilibrium constant (K_(p)) and the degree of dissociation (alpha) ?

Consider the following equilibrium PCl_(5)(g) hArr PCl_(3)(g) + Cl_(2)(g) in a closed container. At a fixed temperature, the volume of the reaction container is halved. For this change, which of the following statements holds true regarding the equilibrium constant (K_(p)) and degree of dissocitation (alpha) ?

For the following equilibrium reaction , N_2O_4(g) hArr 2NO_2(g) NO_2 is 50% of total volume at given temperature . Hence vapour density of the equilibrium mixture is

For which of the following reaction the degree of dissociation (alpha) and equilibrium constant (K_p) are related as K_p =(4alpha^2P)/((1-alpha^2)) ?

For the reaction N_(2)(g)+O_(2)(g)hArr2NO(g) If pressure id increased by reducing the volume of the container then :

Consider the following equilibrium N_(2)O_(4)(g)hArr2NO_(2)(g) Then the select the correct graph , which shows the variation in concentrations of N_(2)O_(4) against concentrations of NO_(2) :

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with

For the reaction, N_2(g) +O_2(g) hArr 2NO(g) Equilibrium constant k_c=2 Degree of association is

For the following equilibrium N_(2)O_(4)(g)hArr 2NO_(2)(g) K_(p) is found to be equal to K_(c) . This is attained when :