Phosphorus pentachloride dissociates as follows in a closed reaction vessel
` PCl_5 (g) hArr PCl_3 (g) + Cl_2( g)`
If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of `PCl_5 ` is x, the partial pressure of `PCl_3 ` will be.

Options

A. `((x)/(x+1))P`
B. `((2x)/(1-x))P`
C. `((x)/(x+1))P`
D. `((x)/(1-x))P`

Answer

A

Explanation

Given: `PCI_(5)(g)hArrPCI_(3)(g)+CI_(2)(g)`
`{:(t=0,1,0,0),(t_(eq),1-x,x,x):}`
Total number of moles`=1-x+x+x=1+x`
Thus partial pressure of `PCI_(3)=((x)/(1+x))P`.