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In equilibrium CH(3)COOH+H(2)OhArrCH(3)C...

In equilibrium `CH_(3)COOH+H_(2)OhArrCH_(3)COO^(-)+H_(3)O^(+)`
The equilibrium constant may change when

A

`CH_(3)COO^(-)` is added

B

`CH_(3)COOH` is added

C

Catalyst is added

D

Mixture is heated

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The correct Answer is:
To determine when the equilibrium constant for the reaction \[ \text{CH}_3\text{COOH} + \text{H}_2\text{O} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}_3\text{O}^+ \] may change, we need to analyze the effects of various factors on the equilibrium constant \( K_{eq} \). ### Step-by-Step Solution: 1. **Understanding the Equilibrium Constant**: The equilibrium constant \( K_{eq} \) for the reaction can be expressed as: \[ K_{eq} = \frac{[\text{CH}_3\text{COO}^-][\text{H}_3\text{O}^+]}{[\text{CH}_3\text{COOH}]} \] Note that the concentration of water \([\text{H}_2\text{O}]\) is not included in the expression because it is a pure liquid. 2. **Effect of Concentration Changes**: - **Adding CH₃COO⁻ (Product)**: When you add more CH₃COO⁻, the concentration of the products increases. According to Le Chatelier's principle, the equilibrium will shift to the left to counteract this change, but the value of \( K_{eq} \) remains unchanged. - **Adding CH₃COOH (Reactant)**: Similarly, if you add more CH₃COOH, the concentration of reactants increases. The equilibrium will shift to the right, but again, \( K_{eq} \) remains unchanged. 3. **Effect of Catalysts**: - **Adding a Catalyst**: A catalyst speeds up the rate of both the forward and reverse reactions equally, thus it does not affect the position of equilibrium or the value of \( K_{eq} \). Therefore, the equilibrium constant remains unchanged. 4. **Effect of Temperature**: - **Heating the Mixture**: According to the Van't Hoff equation, the equilibrium constant is dependent on temperature. If the temperature of the system is changed, the equilibrium constant \( K_{eq} \) will also change. This is the only factor among the options that affects the equilibrium constant. ### Conclusion: The equilibrium constant \( K_{eq} \) may change when the temperature of the system is altered. Therefore, the correct answer is: **The equilibrium constant may change when the mixture is heated.**
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RESONANCE ENGLISH-CHEMICAL EQUILIBRIUM-Advanced Level Problems (Part-1)
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  2. The K(c) for H(2(g)) + I(2(g))hArr2HI(g) is 64. If the volume of the c...

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  3. In equilibrium CH(3)COOH+H(2)OhArrCH(3)COO^(-)+H(3)O^(+) The equilib...

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  4. In the esterification C(2)H(5)OH(l)+CH(3)COOH(l)" an "hArr CH(3)COOC...

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  5. In the following reaction started only with A(8), 2A(8)(g) hArr3A(2)(g...

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  7. For the given reaction at constant pressure, {:(,nA(g)hArr,An(g)),("...

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  8. On decomposition of NH(4)HS , the following equilibrium is estabilishe...

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  11. For the reaction, 4NH(3)(g) + 5O(2)(g)hArr4NO(g) + 6 H(2)O(l), Delt...

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  12. The effect of adding krypton (Kr) gas on position of equilibrium, keep...

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  13. Le-Chatelier's principle is applicable only to a

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  14. Two solid comp0ounds X and Y dissociates at a ceritain temperature as ...

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  19. For the reaction PCl(5(g))hArrPCl(3(g))+Cl(2(g)), the forward reactio...

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  20. Find out InK(eq) for the formation of NO(2) from NO and O(2) at 298 K ...

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