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For the reaction, 4NH(3)(g) + 5O(2)(g)hA...

For the reaction, `4NH_(3)(g) + 5O_(2)(g)hArr4NO(g) + 6`
` H_(2)O(l)`, `Delta H =` positive. At equilibrium the factor that will not affect the concentration of `NH_(3)` is:

A

change in pressure

B

change in volume

C

catalyst

D

None of these

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The correct Answer is:
To solve the problem, we need to analyze the given reaction and determine which factor will not affect the concentration of ammonia (NH₃) at equilibrium. The reaction is: \[ 4NH_3(g) + 5O_2(g) \rightleftharpoons 4NO(g) + 6H_2O(l) \] Given that the change in enthalpy (\(\Delta H\)) is positive, this indicates that the reaction is endothermic. ### Step 1: Analyze the Effect of Pressure - When pressure is applied to a gaseous equilibrium, the reaction will shift towards the side with fewer moles of gas. - In this reaction, the total moles of gas on the reactant side is \(4 + 5 = 9\) moles, and on the product side, it is \(4 + 0 = 4\) moles (since water is a liquid and does not count). - Therefore, increasing pressure will shift the equilibrium to the right, decreasing the concentration of NH₃. Thus, pressure does affect the concentration of NH₃. **Hint:** Consider how changes in pressure influence the side of the reaction with fewer moles of gas. ### Step 2: Analyze the Effect of Volume - Volume is inversely related to pressure. If the volume decreases, the pressure increases, and vice versa. - A decrease in volume will similarly shift the equilibrium towards the side with fewer moles of gas, which again is the product side in this case. - Hence, changing the volume will also affect the concentration of NH₃. **Hint:** Remember that volume changes affect pressure and thus can shift the equilibrium. ### Step 3: Analyze the Effect of a Catalyst - A catalyst speeds up the rate of both the forward and reverse reactions equally but does not change the position of equilibrium. - It does not affect the concentrations of reactants or products at equilibrium; it only helps the system reach equilibrium faster. - Therefore, the presence of a catalyst will not affect the concentration of NH₃. **Hint:** Think about the role of a catalyst in a reaction and its effect on equilibrium. ### Step 4: Analyze the Effect of Temperature - While the question does not explicitly mention temperature, it is important to note that changing temperature can affect the equilibrium position, especially in endothermic reactions. - For an endothermic reaction, increasing the temperature shifts the equilibrium to the right, which would decrease the concentration of NH₃. **Hint:** Consider how temperature changes influence the direction of the equilibrium shift. ### Conclusion The factor that will not affect the concentration of NH₃ at equilibrium is the presence of a catalyst. Therefore, the correct answer is: **Answer:** Catalyst

To solve the problem, we need to analyze the given reaction and determine which factor will not affect the concentration of ammonia (NH₃) at equilibrium. The reaction is: \[ 4NH_3(g) + 5O_2(g) \rightleftharpoons 4NO(g) + 6H_2O(l) \] Given that the change in enthalpy (\(\Delta H\)) is positive, this indicates that the reaction is endothermic. ### Step 1: Analyze the Effect of Pressure - When pressure is applied to a gaseous equilibrium, the reaction will shift towards the side with fewer moles of gas. ...
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