Variation of log(10)K with (1)/(T) is sh...

Variation of `log_(10)K` with `(1)/(T)` is shown by the following graph in which straight line is at `45^(@)` , hence `Delta H^(@)` is:

`+4.606cal`

`-4.606cal`

`2cal`

`-2cal`

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The correct Answer is:

`K=Ae^(-DeltaH//RT)`
`logK=logA-(DeltaH)/(2.303RT)`.
`log K=logA-(DeltaH)/(2.303R)xx(1)/(T)`.
`log K=[-(DeltaH)/(2.303R)]xx(1)/(T)+logA`.
(-DeltaH)/(2.303R)=1`. ltbgt `DeltaH=-2.303R=-4.606cal`.

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Variation of `log_(10)K` with `(1)/(T)` is shown by the following graph in which straight line is at `45^(@)` , hence `Delta H^(@)` is:

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