Home
Class 11
CHEMISTRY
When K(c)gt1 for a chemical reaction,...

When `K_(c)gt1` for a chemical reaction,

A

the equilibrium would be achieved rapidly

B

the equilibrium would be achieved slowly

C

product concentrations would be much greater than reactant concentrations at equilibrium

D

reactant concentraions would be much greater then product concentraions at equilibrium.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the equilibrium constant \( K_c \) for a chemical reaction when \( K_c > 1 \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definition of \( K_c \)**: The equilibrium constant \( K_c \) is defined as the ratio of the concentrations of the products to the concentrations of the reactants, each raised to the power of their respective stoichiometric coefficients. For a general reaction: \[ aA + bB \rightleftharpoons cC + dD \] The equilibrium constant \( K_c \) is given by: \[ K_c = \frac{[C]^c [D]^d}{[A]^a [B]^b} \] 2. **Interpret \( K_c > 1 \)**: When \( K_c > 1 \), it indicates that the concentration of the products is greater than the concentration of the reactants at equilibrium. This means that the reaction favors the formation of products. 3. **Analyze the Implications**: Since \( K_c > 1 \), we can conclude: - The reaction proceeds in the forward direction more than the reverse direction. - At equilibrium, the concentration of products will be significantly higher than that of the reactants. 4. **Evaluate the Given Options**: - **Option A**: "Equilibrium would be achieved rapidly" - This is not necessarily true as the speed of reaching equilibrium does not depend on \( K_c \). - **Option B**: "Equilibrium would be achieved slowly" - This is also not necessarily true for the same reason as above. - **Option C**: "Product concentrations would be much greater than reactant concentrations at equilibrium" - This is true and aligns with our understanding of \( K_c > 1 \). - **Option D**: "Reactant concentration is much higher compared to product concentration at equilibrium" - This is false as it contradicts the condition \( K_c > 1 \). 5. **Select the Correct Option**: Based on the analysis, the correct option is **C**: "Product concentrations would be much greater than reactant concentrations at equilibrium."
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Advanced Level Problems (Part-3)(Stage-2)|3 Videos
  • CHEMICAL EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Advanced Level Problems (Part-3)(Stage-5)|2 Videos
  • CHEMICAL EQUILIBRIUM

    RESONANCE ENGLISH|Exercise Advanced Level Problems (Part-2)(Section-3)|6 Videos
  • CHEMICAL BONDING

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Fundamental Concept )|6 Videos
  • D & F-BLOCK ELEMENTS & THEIR IMPORTANT COMPOUNDS

    RESONANCE ENGLISH|Exercise Match the column|1 Videos

Similar Questions

Explore conceptually related problems

When enthalpy and entropy change for a chemical reaction are -2.5 xx10^(3) cals and 7.4 cals K^(-1) respectively. Predict that reaction at 298 K is

Rate constant for a chemical reaction taking place at 500K is expressed as K=A. e^(-1000) The activation energy of the reaction is :

Activation energy (E_(a)) and rate constants ( k_(1) and k_(2) ) of a chemical reaction at two different temperatures ( T_(1) and T_(2) ) are related by

At 407 K , the rate constant of a chemical reaction is 9.5xx10^(-5)s^(-1) and at 420 K , the rate constant is 1.9xx10^(-4)s^(-1) . Calculate the Arrhenius parameter of the reaction.

Assertion (A) : The rate of a chemical reaction whether exothermic or endothermic increases with temperature. Reason (R ): The rate reaction =k["Reactant"]^(n) and k increases with temperature.

In a chemical reaction , A+2Boverset(K)hArr2c+D, the initial concentration of B was 1.5 times of the concentrations of A , but the equilibrium concentrations of A and B were found to be equal . The equilibrium constant (K) for the aforesaid chemical reaction is :

In a chemical reaction , A+2Boverset(K)hArr2c+D, the initial concentration of B was 1.5 times of the concentrations of A , but the equilibrium concentrations of A and B were found to be equal . The equilibrium constant (K) for the aforesaid chemical reaction is :

Activation energy (E_a) and rate constants (k_1 and k_2) of a chemical reaction at two different temperature (T_1 and T_2) are related by

If the rate expression for a chemical reaction is given by Rate = K[A]^n[B]^m then

For a reaction, aA+bBhArrcC+dD , the reaction quotient Q=([C]_(0)^(c)[D]_(0)^(d))/([A]_(0)^(a)[B]_(0)^(b)) , where [A]_(0) , [B]_(0) , [C]_(0) , [D]_(0) are initial concentrations. Also K_(c)=([C]^(c)[D]^(d))/([A]^(a)[B]^(b)) where [A] , [B] , [C] , [D] are equilibrium concentrations. The reaction proceeds in forward direction if Q lt K_(c) and in backward direction if Q gt K_(c) . The variation of K_(c) with temperature is given by: 2303log(K_(C_(2)))/(K_(C_(1)))=(DeltaH)/(R)[(T_(2)-T_(1))/(T_(1)T_(2))] . For gaseous phase reactions K_(p)=K_(c)(RT)^(Deltan) where Deltan= moles of gaseous products - moles of gaseous reactants. Also -DeltaG^(@)=2.303RT log_(10)K_(c) . The heat or reaction for an endothermic reaction, in equilibrium is 1200 cal , at constant volume is more than at constant pressure at 300 K . The ratio of K_(p)//K_(c) is:

RESONANCE ENGLISH-CHEMICAL EQUILIBRIUM-Advanced Level Problems (Part-3)(Stage-1)
  1. The equilibrium constant for the reaction N(2)+3H(2)hArr2NH(3) is 70 a...

    Text Solution

    |

  2. For the reaction: 4NH(3)(g)+7O(2(g))hArr4NO(2(g))+6H(2)O(g).K(p) is ...

    Text Solution

    |

  3. When K(c)gt1 for a chemical reaction,

    Text Solution

    |

  4. What will be the effect to increased pressure in the following equilib...

    Text Solution

    |

  5. In which reaction will an increase in the volume of the container favo...

    Text Solution

    |

  6. Which of the following changes the value of the equilibrium constant ?

    Text Solution

    |

  7. Consider the equilibrium reaction: 4NH(3((g)))+3O(2((g)))hArr2N(2((g...

    Text Solution

    |

  8. Equilibrium constants K(1) and K(2) for the following equilibria NO(...

    Text Solution

    |

  9. A catalyst speeds up a chemical reraction by

    Text Solution

    |

  10. For the reaction 2HIhArrH(2)(g)+I(2)(g)

    Text Solution

    |

  11. consider the following gaseous equilibrium with equilibrium constant K...

    Text Solution

    |

  12. The equilibrium constant K(c) for the reaction, 2NaHCO(3)(s)hArrNa(2...

    Text Solution

    |

  13. For the following reaction, the value of K change with N(2)(g)+O(2)(...

    Text Solution

    |

  14. For the reaction PCl(3)(g)+Cl(2)(g)rarrPCl(5)(g),K(c) is 26 at 250^(@)...

    Text Solution

    |

  15. At 445^(@)C,K(c) for the following reaction is 0.020. 2HI(g)rarrH(2)...

    Text Solution

    |

  16. A catalyst accelerates a reaction primarily by stablizing the

    Text Solution

    |

  17. The oxidation of SO(2) to SO(3) is an exothermic reaction. The yield o...

    Text Solution

    |

  18. In which of the following reaction K(p) gt K(c) ?

    Text Solution

    |

  19. The K(p)//K(c) ratio for the reaction: 4NH(3)(g)+7O(2)(g)hArr4NO(g)+...

    Text Solution

    |

  20. K(p) for the reaction given below is 1.36 "at" 499K. Which of the fo...

    Text Solution

    |