A compound `(A)` is used in paints instead of salts of lead.Compound(A) is obtained when a white compound `(B)` is strongly heated . Compound `(B)` is insoluble in water but dissolves in sodium hydroxide forming a solution of compound `(C )` the compounds `(A)` on heating with coke gives a metal `(D)` and a gas `(E)` which burns with blue flame . `(B)` also dissolves in ammonium sulphate solution mixed with ammonium hydroxide. solution of compound `(A)` in dilute `HCl` gives a bluish white//white precipitate `(F)` with excess of `(F)` with excees of `K_(4)[Fe(CN)_(6)]` identify `(A)` to `(F)` and explain the reactions.

Answer

(A). ZnO,
(B) `Zn(OH)_(2)`
(C). `Na_(2)ZnO_(2)`
(D) `Zn`,
(E) CO,
(F) `K_(2)Zn_(3)[Fe(CN)_(6)]_(2)`

Explanation

`Zn(OH)_(2)(B)overset(Delta)toZnO(A)+H_(2)O`
`ZnOH_(2)(B)darr+2OH^(-)to[Zn(OH)_(4)]^(2-)`(C) (soluble complex)
`ZnO(A)+Coverset(Delta)toZn(D)+CO(E)`.
`Zn(OH)_(2)(B)+4NH_(3)to[Zn(NH_(3))_(4)]^(2+)` (soluble complex) `+2OH^(-)`
`ZnO+2HCltoZnCl_(2)+H_(2)O`
`3ZnCl_(2)+2K_(4)[Fe(CN)_(6)]toK_(2)Zn_(3)[Fe(CN)_(6)]_(2)darr` (bluish white/white) (F)+6KCl.