Which of the following is true for the speical having `3d^(4)` configuration ?

Options

A. `Cr^(2+)` is reducing in nature.
B. `Mn^(3+)` is oxidising in nature.
C. Both A and B
D. None of these.

Answer

C

Explanation

`Cr^(2+)` is reducing as its configuration changes from `d^(4)` to `d^(3)`, the latter having a half-filled `t_(2g)^(3)` energy level of 3d orbitals in octahedral crystal field spliting. On the toher hand, the change from `Mn^(3+)` to `Mn^(2+)` therefore (C) is correct.