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Identify the incorrect statement....

Identify the incorrect statement.

A

`CuSO_(4)` reacts with KCl in aqueous solution to give `Cu_(2)Cl_(2)`

B

`CuSO_(4)` reacts with Kl in aqueous solution to give `Cu_(2)l_(2)`

C

`CuSO_(4)` reacts with NaOH and glucose in aqueous medium to give `Cu_(2)O`

D

`CuSO_(4)` on strong heating gives CuO.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question of identifying the incorrect statement regarding the reactions involving copper sulfate (CuSO4), let's analyze each statement step by step. ### Step 1: Analyze the First Statement The first statement claims that CuSO4 reacts with KI (potassium iodide) to produce Cu2Cl and not with KCl. - **Reaction with KI**: When CuSO4 reacts with KI, the iodide ions (I-) from KI act as reducing agents. They can reduce Cu²⁺ ions to Cu⁺ ions, leading to the formation of CuI (cuprous iodide) and iodine (I2). - **Incorrect Part**: The statement is incorrect because it implies that CuSO4 does not react with KCl, which is misleading. The reaction with KI is more favorable due to the reducing nature of iodide ions. ### Step 2: Analyze the Second Statement The second statement suggests that CuSO4 reacts with KI to give Cu2I2, I2, and K2SO4. - **Balanced Reaction**: The balanced reaction for the interaction of CuSO4 with KI can be represented as: \[ 2CuSO4 + 4KI \rightarrow Cu2I2 + I2 + 2K2SO4 \] - **Correctness**: This statement is correct as it accurately describes the products formed from the reaction. ### Step 3: Analyze the Third Statement The third statement indicates that CuSO4 reacts with NaOH and glucose in an aqueous medium to produce Cu2O. - **Reaction Overview**: In the presence of NaOH and glucose, Cu²⁺ ions from CuSO4 are reduced to Cu⁺ ions, forming Cu2O (cuprous oxide), which is red in color. - **Correctness**: This statement is also correct as it describes the reaction accurately. ### Step 4: Analyze the Fourth Statement The fourth statement states that copper sulfate on strong heating gives CuO. - **Heating Reaction**: When CuSO4 is heated strongly, it decomposes to form CuO (copper(II) oxide), sulfur dioxide (SO2), and oxygen (O2). - **Balanced Equation**: The reaction can be represented as: \[ 2CuSO4 \rightarrow 2CuO + 2SO2 + O2 \] - **Correctness**: This statement is correct as it accurately describes the thermal decomposition of copper sulfate. ### Conclusion After analyzing all four statements, we find that: - **Incorrect Statement**: The first statement is incorrect because it misrepresents the reaction of CuSO4 with KI and KCl. ### Final Answer The incorrect statement is the first one. ---

To solve the question of identifying the incorrect statement regarding the reactions involving copper sulfate (CuSO4), let's analyze each statement step by step. ### Step 1: Analyze the First Statement The first statement claims that CuSO4 reacts with KI (potassium iodide) to produce Cu2Cl and not with KCl. - **Reaction with KI**: When CuSO4 reacts with KI, the iodide ions (I-) from KI act as reducing agents. They can reduce Cu²⁺ ions to Cu⁺ ions, leading to the formation of CuI (cuprous iodide) and iodine (I2). - **Incorrect Part**: The statement is incorrect because it implies that CuSO4 does not react with KCl, which is misleading. The reaction with KI is more favorable due to the reducing nature of iodide ions. ...
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RESONANCE ENGLISH-D & F-BLOCK ELEMENTS & THEIR IMPORTANT COMPOUNDS -Only one option correct type
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