Feo `Cr_(2)O_(3)``underset(O_(2)) overset(Na_(2)CO_(3))toAoverset(H_(2)SO_(4))toBoverset(KCl)toC`
The hybridisation of compound C and colour of its crystal is

Options

A. In all three compounds, the chromium is in +6 oxidation state
B. [Z] is a deep blueu-violet coloured compound which decomposes rapidly in aqueous solution into `Cr^(3+)` and dioxygen.
C. Saturated solution of [Y] gives bright orange compound, chromic anhydride, with cold and concentrated `H_(2)SO_(4)`.
D. All of these.

Answer

D

Explanation

`4FeCr_(2)O_(4)+8Na_(2)CO_(3)+7O_(2)overset(Fusion)Na_(2)overset(+VI)(CrO_(4))underset(H_(2)O)overset(H^(+))toNa_(2)overset(+VI)(Cr_(2))O_(7)underset(H_(2)O_(2))overset(H^(+))to overset(+VI)(Cr)O(O_(2))_(2)` (deep blue violet) `overset(H_(2)O)toO_(2)+H_(2)O+Cr^(3+)`. (X) (Y) (Z)
`Na_(2)Cr_(2)O_(7)+H_(2)SO_(4)to2CrO_(3)` (bright orange/red-chromic anhydride) +`Na_(2)SO_(4)+H_(2)O`.